1 条题解
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0
C :
#include<stdio.h> int main() { int n,i,r,t,x=0,y=0; scanf("%d",&n); for(i=1;i<=n;i++){ scanf("%d%d",&r,&t); if(r==t){ continue; }else if(r==1){ if(t==2){ x++; }else{ y++; } }else if(r==2){ if(t==1){ y++; }else{ x++; } }else{ if(t==1){ x++; }else{ y++; } } } if(x==y){ printf("tie"); }else if(x>y){ printf("a win"); }else{ printf("b win"); } return 0; }C++ :
#include <iostream> using namespace std; int main(){ //a b代表a和b赢的次数 int n,a = 0,b = 0,i,x,y; cin>>n; for(i = 0;i < n;i++){ cin>>x>>y; if(x == 1 && y == 2 || x == 2 && y == 3 || x == 3 && y == 1){ a++; }else if(x != y){ b++; } } if(a > b){ cout<<"a win"<<endl; }else if(a < b){ cout<<"b win"<<endl; }else{ cout<<"tie"<<endl; } }Java :
import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); int num1 = scanner.nextInt(); // int num2 = scanner.nextInt(); int[][] a = new int[num1][2]; // int[][] b = new int[num1][num2]; int x = 0,y = 0; for (int i = 0; i < num1; i++) { for(int k = 0;k < 2;k++){ a[i][k] = scanner.nextInt(); } }for (int i = 0; i < num1; i++) { if(a[i][0] == 1 && a[i][1] == 2 || a[i][0] == 2 && a[i][1] == 3 || a[i][0] == 3 && a[i][1] == 1) x++; else if(a[i][1] == 1 && a[i][0] == 2 || a[i][1] == 2 && a[i][0] == 3 || a[i][1] == 3 && a[i][0] == 1)y++; } if(x > y) System.out.println("a" + " " +"win"); else if(x < y) System.out.println("b" + " " + "win"); else System.out.println("tie"); }public static void paiXu(int[] a,int length){ int temp; for(int i = 0;i < length - 1;i++){ for(int k = 0;k < length - i - 1;k++){ if(a[k] > a[k + 1]){ temp = a[k]; a[k] = a[k + 1]; a[k + 1] = temp; } } } } public static void paiXud(int[] a){ int temp; for(int i = 0;i < a.length - 1;i++){ for(int k = 0;k < a.length - i - 1;k++){ if(a[k] < a[k + 1]){ temp = a[k]; a[k] = a[k + 1]; a[k + 1] = temp; } } } } public static void paiXux(int[] a){ int temp; for(int i = 0;i < a.length - 1;i++){ for(int k = 0;k < a.length - i - 1;k++){ if(a[k] > a[k + 1]){ temp = a[k]; a[k] = a[k + 1]; a[k + 1] = temp; } } } } public static int MAX2(int[][] a){ int max = a[0][0]; for (int i = 0; i < a.length; i++) { for(int j = 0;j < a[0].length;j++){ if(max < a[i][j])max = a[i][j]; } } return max; }public static int MIN2(int[][] a){ int min = a[0][0]; for (int i = 0; i < a.length; i++) { for(int j = 0;j < a[0].length;j++){ if(min > a[i][j])min = a[i][j]; } } return min; } public static int MAX(int[] a){ int max = a[0]; for (int i = 0; i < a.length; i++) { if(max < a[i]){ max = a[i]; } } return max; } public static int MIN(int[] a){ int min = a[0]; for (int i = 0; i < a.length; i++) { if(min > a[i]){ min = a[i]; } } return min; } public static int sum(int a){ int x,s = 0; while(a != 0){ x = a % 10; s = s + x; a /= 10; } return s; } public static boolean isPrime(int a){ if(a <= 1)return false; else for(int i = 2;i <= Math.sqrt(a);i++){ if(a % i == 0)return false; }return true; } public static long qiuYu(long i){ long a; a = i % 10; return a; } public static int daoXu(int x){ int s = 0,m; while(x != 0){ m = x % 10; s = s * 10 + m; x /= 10; } return s; } public static int jiaWei(int x){ int s = 0,m; while(x != 0){ m = x % 10; s = s + m; x /= 10; } return s; } public static int fun(int x){ if(x == 1 || x == 2)return 1; else return fun(x - 1) + fun(x - 2); } }Python :
n=int(input()) a=[[0 for i in range(2)] for j in range(n)] js1=0 js2=0 for i in range(n): sr=input().split() for j in range(2): a[i][j]=int(sr[j]) if(a[i][0]-a[i][1]==-1 or a[i][0]-a[i][1]==2): js1=js1+1 elif(a[i][0]-a[i][1]==1 or a[i][0]-a[i][1]==-2): js2=js2+1 if(js1>js2): print("a win") elif(js1==js2): print("tie") else: print("b win")
- 1
信息
- ID
- 386
- 时间
- 1000ms
- 内存
- 512MiB
- 难度
- 9
- 标签
- 递交数
- 9
- 已通过
- 7
- 上传者