1 条题解
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0
C :
#include <stdio.h> //回文数 int huiWen(int x){ int h=0,y = x; while(x > 0){ h = h * 10 + x % 10; x /= 10; } if(h == y) return 1; else return 0; } int main(){ int n,m; scanf("%d %d",&n,&m); int a[n][m],i,j; //二维数组 int s = 0; //回文数个数 //二维数组赋值,并删选回文数 for(i = 0;i < n;i++){ for(j = 0;j < m;j++){ scanf("%d",&a[i][j]); if(huiWen(a[i][j])) s++; } } int b[s],z=0; //存放回文数 for(i = 0;i < n;i++){ for(j = 0;j < m;j++){ if(huiWen(a[i][j])) b[z++] = a[i][j]; } } //遍历回文数 for(i = 0;i < s;i++){ printf("%d\n",b[i]); } return 0; }C++ :
#include <bits/stdc++.h> using namespace std; //判断一个四位数是否是回文 bool huiwen(int n){ bool r = false;//假设不是回文 int q,b,s,g; q = n / 1000; b = n / 100 % 10; s = n / 10 % 10; g = n % 10; if(n < 10){ r = true; }else if(n >= 10 && n < 100 && g == s){ r = true; }else if(n >= 100 && n < 1000 && g == b){ r = true; }else if(n >= 1000 && n < 10000 && g == q && s == b){ r = true; } return r; } int main(){ int n,m,a[110][110],i,j,c = 0; cin>>n>>m; for(i = 0;i < n;i++){ for(j = 0;j < m;j++){ cin>>a[i][j]; } } for(i = 0;i < n;i++){ for(j = 0;j < m;j++){ if(huiwen(a[i][j])){ cout<<a[i][j]<<endl; } } } }Java :
import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); int num1 = scanner.nextInt(); int num2 = scanner.nextInt(); int[][] a = new int[num1][num2]; // int[][] b = new int[num1][num2]; int x = 0,y = 0; for (int i = 0; i < num1; i++) { for(int k = 0;k < num2;k++){ a[i][k] = scanner.nextInt(); } }for (int i = 0; i < num1; i++) { for(int k = 0;k < num2;k++){ if(a[i][k] == daoXu(a[i][k])) System.out.println(a[i][k]); } } }public static void paiXu(int[] a,int length){ int temp; for(int i = 0;i < length - 1;i++){ for(int k = 0;k < length - i - 1;k++){ if(a[k] > a[k + 1]){ temp = a[k]; a[k] = a[k + 1]; a[k + 1] = temp; } } } } public static void paiXud(int[] a){ int temp; for(int i = 0;i < a.length - 1;i++){ for(int k = 0;k < a.length - i - 1;k++){ if(a[k] < a[k + 1]){ temp = a[k]; a[k] = a[k + 1]; a[k + 1] = temp; } } } } public static void paiXux(int[] a){ int temp; for(int i = 0;i < a.length - 1;i++){ for(int k = 0;k < a.length - i - 1;k++){ if(a[k] > a[k + 1]){ temp = a[k]; a[k] = a[k + 1]; a[k + 1] = temp; } } } } public static int MAX2(int[][] a){ int max = a[0][0]; for (int i = 0; i < a.length; i++) { for(int j = 0;j < a[0].length;j++){ if(max < a[i][j])max = a[i][j]; } } return max; }public static int MIN2(int[][] a){ int min = a[0][0]; for (int i = 0; i < a.length; i++) { for(int j = 0;j < a[0].length;j++){ if(min > a[i][j])min = a[i][j]; } } return min; } public static int MAX(int[] a){ int max = a[0]; for (int i = 0; i < a.length; i++) { if(max < a[i]){ max = a[i]; } } return max; } public static int MIN(int[] a){ int min = a[0]; for (int i = 0; i < a.length; i++) { if(min > a[i]){ min = a[i]; } } return min; } public static int sum(int a){ int x,s = 0; while(a != 0){ x = a % 10; s = s + x; a /= 10; } return s; } public static boolean isPrime(int a){ if(a <= 1)return false; else for(int i = 2;i <= Math.sqrt(a);i++){ if(a % i == 0)return false; }return true; } public static long qiuYu(long i){ long a; a = i % 10; return a; } public static int daoXu(int x){ int s = 0,m; while(x != 0){ m = x % 10; s = s * 10 + m; x /= 10; } return s; } public static int jiaWei(int x){ int s = 0,m; while(x != 0){ m = x % 10; s = s + m; x /= 10; } return s; } public static int fun(int x){ if(x == 1 || x == 2)return 1; else return fun(x - 1) + fun(x - 2); } }Python :
n,m=list(map(int,input().split())) a=list() for i in range(n): a.append(list(map(int,input().split()))) js,os=0,0 for i in range(n): for j in range(m): str1=str(a[i][j]) if str1==str1[::-1]: print(str1)
- 1
信息
- ID
- 383
- 时间
- 1000ms
- 内存
- 512MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者