1 条题解
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0
C :
#include<stdio.h> void main(){ int a[100][100]; int i,j,n,m,c=0,s=0; scanf("%d %d",&n,&m); for(i=0;i<n;i++){ for(j=0;j<m;j++){ scanf("%d",&a[i][j]); } } for(i=0;i<n;i++){ for(j=0;j<m;j++){ if(a[i][j]%2!=0){ c++; } if(a[i][j]%2==0){ s++; } } } printf("%d %d",c,s); }C++ :
#include <bits/stdc++.h> using namespace std; int main(){ int n,m,a[110][110],x = 0,y = 0; int i,j; cin>>n>>m; for(i = 0;i < n;i++){ for(j = 0;j < m;j++){ cin>>a[i][j]; if(a[i][j] % 2 != 0){ x++; }else{ y++; } } } cout<<x<<" "<<y<<endl; }Pascal :
var a:array[1..1000,1..1000] of longint; x,y,i,j,m,n:longint; begin read(m,n); for i:=1 to m do for j:=1 to n do begin read(a[i,j]); if a[i,j] mod 2=1 then inc(x) else inc(y); end; write(x,' ',y); end.Java :
import java.util.*; public class Main { public static void main(String[] args){ Scanner sc = new Scanner(System.in); int n = sc.nextInt(); int m = sc.nextInt(); int[][] a = new int[n][m]; for(int i = 0;i < n;i++){ for(int j = 0;j <m;j++){ a[i][j]=sc.nextInt(); } } int x=0; int y=0; for(int i = 0;i < n;i++){ for(int j = 0;j <m;j++){ if(a[i][j]%2==0) { y++; }else { x++; } } } System.out.print(x+" "+y); } }Python :
n,m=list(map(int,input().split())) a=list() for i in range(n): a.append(list(map(int,input().split()))) js,os=0,0 for i in range(n): for j in range(m): if a[i][j]%2==1: js=js+1 else: os=os+1 print(js,os)
- 1
信息
- ID
- 378
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- 10
- 标签
- 递交数
- 2
- 已通过
- 2
- 上传者