1 条题解
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0
C :
#include <stdio.h> float ti(int a,int b,int c) { return 1.0*(a+b)*c/2; } int main() { int a[100][100]; int n; float s=0; scanf("%d",&n); int i,j; for(i=0;i<n;i++){ for(j=0;j<3;j++){ scanf("%d",&a[i][j]); } if(s<ti(a[i][0],a[i][1],a[i][2])) s=ti(a[i][0],a[i][1],a[i][2]); } printf("%.1f",s); return 0; }C++ :
#include<bits/stdc++.h> using namespace std; int main(){ double max=0; int n; cin>>n; int a[100][100]; int i,j; for(i=0;i<n;i++){ for(j=0;j<3;j++){ cin>>a[i][j]; } } double mianji; for(i=0;i<n;i++){ mianji=(a[i][0]+a[i][1])*1.0*a[i][2]/2; if(mianji>max){ max=mianji; } } cout<<fixed<<setprecision(1)<<max; return 0; }Pascal :
var a:array[1..100000] of real; b,c,d:array[1..100000] of longint; i,n:longint; max:real; begin read(n); for i:=1 to n do read(b[i],c[i],d[i]); for i:=1 to n do a[i]:=(b[i]+c[i])*d[i]/2; for i:=1 to n do if a[i]>max then max:=a[i]; write(max:0:1); end.Java :
import java.util.*; public class Main { public static void main(String[] args){ Scanner sc = new Scanner(System.in); int n = sc.nextInt(); int[][] a = new int[n][3]; for(int i = 0;i < n;i++){ for(int j=0;j<3;j++) { a[i][j]=sc.nextInt(); } } double [] b=new double[100]; for(int i = 0;i < n;i++){ b[i] = (a[i][1]+a[i][0])*a[i][2]*1.0/2; } double max=b[0]; for(int i=1;i<n;i++) { if(b[i]>max) { max=b[i]; } } String x=String.format("%.1f",max); System.out.println(x); } }Python :
class Tx: def __init__(self,c,k,g): self.c=c self.k=k self.g=g self.s=(c+k)*g/2 n=int(input()) list1=list() for i in range(n): c,k,g=list(map(int,input().split())) list1.append(Tx(c,k,g)) list2=sorted(list1,key=lambda t:(-t.s)) print(list2[0].s)
- 1
信息
- ID
- 310
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者