1 条题解
-
0
C :
#include<stdio.h> int main() { int n,i ,j; scanf("%d",&n); int a[n][n]; for(i=0;i<n;i++){ a[i][0]=1; for(j=1;j<=n-i-1;j++){ a[i][j]=a[i][j-1]+1; } for(j=n-i;j<n;j++){ a[i][j]=a[i][j-1]; } } for(i=0;i<n;i++){ for(j=0;j<n;j++){ printf("%3d",a[i][j]); } printf("\n"); } return 0; }C++ :
#include<bits/stdc++.h> using namespace std; int a[110][110]; int main() { int n; cin>>n; for(int i=0;i<n;i++) { for(int j=i;j<n;j++) { for(int k=0;k<n-i;k++) { a[k][j]++; } } } for(int i=0;i<n;i++) { for(int j=0;j<n;j++) { cout<<setw(3)<<a[i][j]; } cout<<endl; } return 0; }Pascal :
var i,n:longint; function max(a,b:longint):longint; begin if(a>b)then exit(a); exit(b); end; begin readln(n); for i:=1 to n*n do begin write(n-max(n-((i-1) mod n+1),(i-1) div n):3); if(i mod n = 0)then writeln; end; end.Java :
import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner sc= new Scanner(System.in); int b= sc.nextInt(); int[][] a =new int[b][b]; for(int n=0;n<b;n++){ for(int m=0;m<b;m++){ if(m+1<b-n){ System.out.printf("%3d",m+1); } if(m+1>=b-n){ System.out.printf("%3d",b-n); } } System.out.println(""); } } }Python :
n = int(input()) a = [[0 for j in range(n)] for i in range(n)] for i in range(n): # 先定好第一列数字 a[i][0] = 1 for j in range(1, n - i): a[i][j] = a[i][j - 1] + 1 for j in range(n - i, n): a[i][j] = a[i][j - 1] for i in range(n): for j in range(n): print('%3d' % a[i][j], end='') print()
- 1
信息
- ID
- 196
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者