1 条题解
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0
C :
#include<stdio.h> int main() { int n,i,j; scanf("%d",&n); int a[n][n]; for(i=0;i<n;i++){ a[i][0]=i+1; for(j=1;j<=n-i-1;j++){ a[i][j]=a[i][j-1]; } for(j=n-i;j<n;j++){ a[i][j]=a[i][j-1]-1; } } for(i=0;i<n;i++){ for(j=0;j<n;j++){ printf("%3d",a[i][j]); } printf("\n"); } return 0; }C++ :
#include<bits/stdc++.h> using namespace std; int a[110][110]; int main() { int n; cin>>n; for(int i=0;i<n;i++) { for(int j=i;j<n;j++) { for(int k=0;k<n-i;k++) { a[j][k]++; } } } for(int i=0;i<n;i++) { for(int j=0;j<n;j++) { cout<<setw(3)<<a[i][j]; } cout<<endl; } return 0; }Pascal :
var i,j,m:longint; a:array[1..100,1..100]of longint; begin read(m); for i:=1 to m do begin for j:=1 to m-i+1 do a[j,i]:=i; for j:=1 to m-i+1 do a[m-i+1,m-j+1]:=i;end; for i:=1 to m do begin for j:=1 to m do write(' ',a[j,i]); writeln;end; end.Java :
import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner sc= new Scanner(System.in); int b= sc.nextInt(); int[][] a =new int[b][b]; for(int n=0;n<b;n++){ for(int m=0;m<b;m++){ if(b-m>=n+1){ System.out.printf("%3d",n+1); } if(b-m<n+1){ System.out.printf("%3d",b-m); } } System.out.println(""); } } }Python :
n = int(input()) a = [[0 for j in range(n)] for i in range(n)] for i in range(n): # 先定好第一列数字 a[i][0] = i + 1 for j in range(1, n - i): a[i][j] = a[i][j - 1] for j in range(n - i, n): a[i][j] = a[i][j - 1] - 1 for i in range(n): for j in range(n): print('%3d' % a[i][j], end='') print()
- 1
信息
- ID
- 195
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者