1 条题解
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0
C :
#include<stdio.h> int main() { int n,i,j; scanf("%d",&n); int a[n][n]; for(i=0;i<n;i++){ a[i][0]=n-i; for(j=1;j<=i;j++){ a[i][j]=a[i][j-1]; } for(j=i+1;j<n;j++){ a[i][j]=a[i][j-1]-1; } } for(i=0;i<n;i++){ for(j=0;j<n;j++){ printf("%3d",a[i][j]) ; } printf("\n"); } return 0; }C++ :
#include<iostream> #include<iomanip> using namespace std; int main(){ int n; int a[11][11]; cin>>n; for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { if (i >=j) { a[i][j] =n-i; } else { a[i][j] = n-j; } } } for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { cout<<setw(3)<<a[i][j]; } cout<<endl; } }Java :
import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner sc= new Scanner(System.in); int b= sc.nextInt(); int[][] a =new int[b][b]; for(int n=0;n<b;n++){ for(int m=0;m<b;m++){ if(b-m>b-n){ System.out.printf("%3d",b-n); } if(b-m<=b-n){ System.out.printf("%3d",b-m); } } System.out.println(""); } } }Python :
n = int(input()) a = [[0 for j in range(n)] for i in range(n)] for i in range(n): # 先定好第一列数字 a[i][0] = n - i for j in range(1, i + 1): a[i][j] = a[i][j - 1] for j in range(i + 1, n): a[i][j] = a[i][j - 1] - 1 for i in range(n): for j in range(n): print('%3d' % a[i][j], end='') print()
- 1
信息
- ID
- 192
- 时间
- 1000ms
- 内存
- 512MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者