1 条题解

  • 0
    @ 2025-10-10 15:45:28

    C :

    #include<stdio.h>
    int main(){
    	int n,i,j;
    	scanf("%d",&n);
    	int a[n][n];
    	for(i=0;i<n;i++){
    		a[i][0]=i+1;
    		for(j=1;j<n-i;j++){
    			a[i][j]=a[i][j-1]+1;
    		}
    		for(j=n-i;j<n;j++){
    			if(j==n-i){
    				a[i][j]=1;
    			}else{
    				a[i][j]=a[i][j-1]+1;
    			}
    		}
    	}
    	for(i=0;i<n;i++){
    		for(j=0;j<n;j++){
    			printf("%3c",(a[i][j]+'A'-1));
    		}
    		printf("\n");
    	} 
    return 0;
    } 
    
    
    
    
    
    
    
    
    

    C++ :

    #include <iostream>
    #include <iomanip>
    using namespace std;
    
    int main(){
    	int a[10][10];
    	int i,j,n;
    	cin>>n;
    	
    	for (i = 0;i < n;i++){
    		for (j = 0;j < n;j++){
    			if (i + j + 1 <= n){
    				a[i][j] = i + j + 1 + 64;
    			}else{
    				a[i][j] = i + j + 1 - n + 64;
    			}
    		}
    	}
    	
    	for (i = 0;i < n;i++){
    		for (j = 0;j < n;j++){
    			cout<<setw(3)<<char(a[i][j]);
    		}
    		cout<<endl;
    	}
    }
    

    Pascal :

    var i,j,n:longint;
    begin
      readln(n);
      for i:=1 to n do
      begin
        for j:=1 to n do
          if i+j<=n+1 then write(chr(i+j-2+ord('A')):3)
            else write(chr(i+j-n-2+ord('A')):3);
        writeln;
      end;
    end.
    

    Java :

    import java.util.Scanner;
    public class Main {
    	public static void main(String[] args) {
    		Scanner sc= new Scanner(System.in);
    		int b= sc.nextInt();
    		int[][] a =new int[b][b];
    		char c;
    				
    		for(int n=0;n<b;n++){
    			for(int m=0;m<b;m++){
    				if(n+m+1<=b){
    					c = (char) (n+m+65);
    					System.out.printf("%3c",c);
    				}
    				if(n+m+1>b){
    					c = (char) (n+m+65-b);
    					System.out.printf("%3c",c);
    				}
    			}
    			System.out.println("");
    		}
    		
    		
    	}
    
    }
    

    Python :

    def getList(m,n):
        '''
          m 行数
          n 列数
          返回的是m行n列的二维数组,默认值为0
        '''
        ma = [ [0 for i in range(n)] for i in range(m) ]
        return ma
    
    def printList(arr):
        for i in arr:
            for j in i:
                print('%3s' %(chr(j + 64)) ,end='')
            print();
    
    n = int( input() );
    arr = getList(n,n)
    for i in range(0,n):
        k = i
        for j in range(0,n):
            arr[i][j] = k + 1
            k += 1
            if i + j == n - 1:
              k = 0
            
    printList(arr)
    '''
    1 2 3 4 5
    2 3 4 5 1
    3 4 5 1 2
    
    '''
    
    • 1

    信息

    ID
    189
    时间
    1000ms
    内存
    512MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者