1 条题解
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0
C :
#include<stdio.h> int main() { int n,i,j; scanf("%d",&n); int a[n][n]; for(i=0;i<n;i++){ for(j=0;j<n;j++){ a[i][j]=0; if(i+j==n-1){ a[i][j]=1; } } } for(i=0;i<n;i++){ for(j=0;j<n;j++){ printf("%3d",a[i][j]); } printf("\n"); } return 0; }C++ :
#include <iostream> #include <iomanip> #include <cmath> #include <cstdio> using namespace std; int main(){ int n,i,j,a[110][110]; cin>>n; for(i=1;i<=n;i++){ for(j=1;j<=n;j++){ if(i+j!=n+1) a[i][j]=0; else a[i][j]=1; } } for(i=1;i<=n;i++){ for(j=1;j<=n;j++){ cout<<setw(3)<<a[i][j]; } cout<<endl; } }Pascal :
var k,j,n,i:longint; begin readln(n); for j:=n downto 1 do begin for i:=1 to n do if j=i then write(1:3) else write(0:3); writeln; end; end.Java :
import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner sc= new Scanner(System.in); int b= sc.nextInt(); int[][] a =new int[b][b]; int s=0; for(int n=0;n<b;n++){ for(int m=b-1;m>=0;m--){ if(n==s&&b-1-s==m){ a[n][m]=1; s++; } } } for(int n=0;n<b;n++){ for(int m=0;m<b;m++){ System.out.printf("%3d",a[n][m]); } System.out.println(""); } } }Python :
def getList(m,n): ''' m 行数 n 列数 返回的是m行n列的二维数组,默认值为0 ''' ma = [ [0 for i in range(n)] for i in range(m) ] return ma def printList(arr): for i in arr: for j in i: print('%3d' %(j),end='') print(); n=int(input()) arr = getList(n,n) for i in range(0,n): for j in range(0,n): if i+j==n-1: arr[i][j] = 1 # else: # arr[i][j] = 0 #可加可不加 默认值为0 printList(arr)
- 1
信息
- ID
- 186
- 时间
- 1000ms
- 内存
- 512MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者