1 条题解
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0
C :
#include<stdio.h> int main(){ int n,i,j; scanf("%d",&n); int a[n][n]; int s = 1; for(i = 1;i <= n;i++){ for(j = 1;j <= n;j++){ a[i][j] = s; s++; } } for(i = n;i >= 1;i--){ for(j = 1;j <= n;j++){ printf("%3d",a[i][j]); } printf("\n"); } return 0; }C++ :
#include <iostream> #include <iomanip> #include <cmath> #include <cstdio> using namespace std; int main(){ int n,i,j,a[110][110]; cin>>n; for(i=1;i<=n;i++){ for(j=1;j<=n;j++){ a[i][j]=((i-1)*n)+j; } } for(i=n;i>=1;i--){ for(j=1;j<=n;j++){ cout<<setw(3)<<a[i][j]; } cout<<endl; } }Pascal :
var k,j,n,i,m:longint; begin readln(n); m:=n*n-n+1; k:=m; for j:=1 to n do begin if j<>1 then k:=m-n; for i:=1 to n do begin write(k:3); if i=1 then m:=k; inc(k); end; writeln; end; end.Java :
import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner sc= new Scanner(System.in); int b= sc.nextInt(); int[][] a =new int[b][b]; int s=0; for(int n=0;n<a.length;n++){ for(int m=0;m<a[n].length;m++){ a[n][m]=s+1; s++; } } for(int n=a.length-1;n>=0;n--){ for(int m=0;m<a[n].length;m++){ System.out.printf("%3d",a[n][m]); } System.out.println(""); } } }Python :
n = int(input()); def getArray(m,n): ''' :param m: 行 :param n: 列 :return: m行n列的二维数组 ''' array = [[0for i in range(n)] for i in range(m)]; return array; x = getArray(n,n); k = 1 for i in range(len(x)-1,-1,-1): for j in range(0,len(x[i])): x[i][j] = k; k += 1 #打印二维数组的代码 for i in x: for j in i: print('%3d'%(j),end='') print()
- 1
信息
- ID
- 180
- 时间
- 1000ms
- 内存
- 512MiB
- 难度
- 10
- 标签
- 递交数
- 1
- 已通过
- 1
- 上传者