1 条题解
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0
C :
#include <stdio.h> #include <stdlib.h> int main() { int n; scanf("%d",&n); int i; int sum1=0,sum2=0; for(i=1;i<=n;i++) { if(i%2!=0) sum1+=i; else sum2+=i; } printf("%d %d",sum1,sum2); return 0; } //Author: ITProgrammerC++ :
#include <iostream> using namespace std; int main(){ int i,n,s=0,c=0; cin>>n; for(i=1;i<=n;i=i+2){ s=s+i; }for(i=2;i<=n;i=i+2){ c=c+i; }cout<<s<<"\\"<<c<<endl; }Pascal :
program ex_1091; var n,i,s,r:integer; begin readln(n); for i:=1 to n do if i mod 2=0 then r:=r+i else s:=s+i; writeln(s,' ',r); end.Java :
import java.util.Scanner; public class Main{ public static void main(String[] args) { int n=new Scanner(System.in).nextInt(); int sum_j=0; int sum_o=0; for(int i=1;i<=n;i++){ if(i%2==0){ sum_o=sum_o+i; }else{ sum_j=sum_j+i; } } System.out.println(sum_j+"\\"+sum_o); } }Python :
n = int(input()) s = 0 t = 0 for i in range(1, n + 1): if i % 2 == 0: s += i if i % 2 == 1: t += i print(str(t)+' '+str(s))
- 1
信息
- ID
- 89
- 时间
- 1000ms
- 内存
- 32MiB
- 难度
- 10
- 标签
- 递交数
- 4
- 已通过
- 3
- 上传者