1 条题解

  • 0
    @ 2025-10-10 15:45:25

    C :

    #include<stdio.h>
    int main()
    {
    	int n;
    	scanf("%d",&n);
    	int x;
    	for(x=1;x<=n;x++){
    		int y;
    		for(y=1;y<=n-x;y++){
    			printf(" ");
    		}
    		int z;
    		for(z=1;z<=2*x-1;z++){
    			printf("%d",x);
    		}
    		printf("\n");
    	}
    	return 0;
    }
    

    C++ :

    #include<iostream>
    using namespace std;
    
    int main(){
    	
    	int n,k;
    	cin>>n;
    	k=1;
    	for(int i=1;i<=n;i++){
    		for(int j=1;j<=n-i;j++){
    			cout<<" ";
    		}
    		for(int j=1;j<=2*i-1;j++){
    			cout<<k;
    		}
    		k++;
    		cout<<endl;
    	}
    }
    
    

    Pascal :

    var n,i,k:longint;
    begin
      readln(n);
      for i:=1 to n do
      begin
         for k:=1 to i*2-1 do if k=1 then write(i:n-i+1) else write(i);
         writeln;
      end;
    end.
    

    Java :

    import java.util.Scanner;
    public class Main
    {
        public static void main(String[] args)
        { Scanner s = new Scanner(System.in);
               int n = s.nextInt();
              
            for(int i = 1;i <= n;i ++)
            {
                 for(int j = n - i;j >= 1;j --)
                 {
                     System.out.print(" ");
                 }
                 for(int k = 1;k <= 2 * i - 1;k ++)
                 {
                     System.out.print(i);
                 }
                     System.out.println();
            }
                 
        }
    } 
    

    Python :

    #!/usr/bin/env python3
         
    n = int(input())
    m = 1
    k = n-1
    s = 1
    for i in range(0,n,1):
         for j in range(0,k,1):
             print(" ",end="")
         for j in range(0,m,1):
             print(s,end="")
         print()
         m+=2
         k-=1
         s+=1 
    
    • 1

    信息

    ID
    8
    时间
    1000ms
    内存
    512MiB
    难度
    10
    标签
    递交数
    3
    已通过
    3
    上传者