1 条题解

  • 0
    @ 2025-10-10 15:45:25

    C :

    #include<stdio.h>
    #include<string.h>
    int main(){		
    	char s[1000];
    	gets(s);
    	int len=strlen(s),i,n=0;
    	for(i=0;i<len;i++){
    		if(s[i]>='A'&&s[i]<='Z'){
    			n++;
    		}
    		
    	}
    	printf("%d",n);
    	return 0; 
    	}
    

    C++ :

    #include <iostream>
    using namespace std;
     
    int getNum(char *s){
        int c = 0;
        while(*s != '\0'){
            if(*s >= 'A' && *s <= 'Z'){
                c++;
            }
            s++;
        }
        return c;
    }
     
    int main(){
        char s[100];
        gets(s);
        int c = getNum(s);
        cout<<c<<endl;
    } 
    

    Pascal :

    var ch:char;s,j,i:integer;
    begin
    read(ch);
    repeat
    if(ch>='A')and(ch<='Z')then s:=s+1;
    read(ch);
    until ch='.';
    readln;
    writeln(s);
    end. 
    

    Java :

    import java.util.Scanner;
    public class Main{
    	public static void main(String[] args) {
    		String str=new Scanner(System.in).nextLine();
    		String[] strArray=str.split("\\.");
    		String s=strArray[0];
    		char[] charArray=s.toCharArray();
    		int count=0;
    		for(int i=0;i<charArray.length;i++){
    			if((int)(charArray[i])>=65&&(int)(charArray[i])<=90){
    				count++;
    			}
    		}
    		System.out.println(count);
    	}
    }
    
    

    Python :

    import string
    word = "PRC,PRC,I'm from China"
    s = 0
    for i in word:
        if  i>='A' and i<='Z':
            s += 1
    print(s)
    
    • 1

    信息

    ID
    7
    时间
    1000ms
    内存
    512MiB
    难度
    10
    标签
    递交数
    5
    已通过
    3
    上传者