1 条题解
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0
C :
#include<stdio.h> int main(){ int n,i,j,z; scanf("%d",&n); //控制输出的行数 for(i = n;i >= 1;i--){ //控制每行输出空格量 for(j = 0;j < n-i;j++){ printf(" "); } //控住输出的* for(z=1;z <= 2 * i - 1;z++){ printf("*"); } //负责换行 printf("\n"); } }C++ :
#include <iostream> using namespace std; int main (){ int i,j,n; cin>>n; char c; for(i=n;i>=1;i--){ for(j=1;j<=n-i;j++){ cout<<" "; } for(j=1;j<=i+i-1;j++){ cout<<"*"; } cout<<endl; } }Pascal :
var a,b,i,c,j,k:longint; begin read(a); b:=0; for i:=a downto 1 do begin for j:=b downto 1 do write(' '); b:=b+1; c:=i*2-1; for k:=1 to c do write('*'); writeln; end; end.Java :
import java.util.Scanner; public class Main{ public static void main(String[] args){ Scanner scanner=new Scanner(System.in); int n=scanner.nextInt(); for(int i=1;i<=n;i++){ for(int j=1;j<=i-1;j++){ System.out.print(" "); } for(int j=1;j<=2*(n-i)+1;j++){ System.out.print("*"); } System.out.println(); } } }Python :
n = int(input()); for i in range(1, n + 1): for k in range(1, i): print(end=' ') for x in range(i ,2*n-i+1 ): print('*', end = '') print()
- 1
信息
- ID
- 69
- 时间
- 1000ms
- 内存
- 512MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者