1 条题解

  • 0
    @ 2025-10-10 15:45:26

    C :

    int main(){ 
    	int n,i,j,z;
    	scanf("%d",&n);
    	//控制输出的行数 
    	for(i = 1;i <= n;i++){
    		//控制每行输出空格量 
    		for(j = 0;j < n - i;j++){
    			printf(" "); 
    		}
    		//控住输出的*
    		for(z=1;z <= 2 * i + 1;z++){
    			printf("*");
    		} 
    		//负责换行 
    		printf("\n");
    	}
    
    } 
    
    

    C++ :

    #include<iostream>
    using namespace std;
    int main(){ 
       int i,j,k,n;
       cin>>n;
       for(i = 1;i <= n;i++)
       { 
              for(j = 1;j <= n - i;j++)
              { 
        cout<<" ";
     }
     for(k = 1;k <= 2 * i + 1;k++)
     { 
        cout<<"*";
     }
     cout<<endl;
       }
       return 0; 
    }   
    
    

    Pascal :

    var a,b,i,c,j,k:longint;
    begin
    read(a);
    b:=a-1;
    for i:=1 to a do
    begin
    for j:=b downto 1 do
    write(' ');
    b:=b-1;
    c:=i*2-1;
    write('**');
    for k:=1 to c do
    write('*');
    writeln;
    end;
    end.
    

    Java :

    import java.util.Scanner;
    public class Main{
    	public static void main(String[] args){
    		Scanner scanner=new Scanner(System.in);
    		int n=scanner.nextInt();
    		for(int i=1;i<=n;i++){
    			for(int j=1;j<=n-i;j++){
    				System.out.print(" ");
    			}
    			for(int j=1;j<=2*i+1;j++){
    				System.out.print("*");
    			}
    			System.out.println();
    		}
    	}
    }
    

    Python :

    n = int(input());
    for i in range(1, n + 1):
        for k in range(1, n -i + 1):
            print(' ',end = '')
        for x in range(1, 2 * i +2):
            print('*', end = '')
        print()
    
    
    
    • 1

    信息

    ID
    68
    时间
    1000ms
    内存
    512MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者