1 条题解

  • 0
    @ 2025-10-10 15:45:26

    C :

    #include<stdio.h>   
    
    int main(){ 
    	int i,n,c=0;
    	scanf("%d",&n);
    
    	
    	for(i = 5;i <= n;i++){
    		int w = i / 10000;
    		int q = i / 1000 % 10;
    		int b = i / 100 % 10;
    		int s = i / 10 % 10;
    		int g = i % 10;
    		
    		if((w == 5 || q == 5 || b == 5 || s == 5 || g == 5) && i % 5 == 0){
    		
    			c++;
    		}
    	}
    	
    	printf("%d",c);
    	return 0;
    } 
    

    C++ :

    #include<iostream>
    #include<math.h>
    using namespace std;
    int main(){
        int n,i,a,b,c,d,e,f = 0;
        cin>>n;
        i = 1;
        while(i <= n){ 
      a = i / 10000;
      b = i / 1000 % 10;
      c = i / 100 % 10;
      d = i / 10 % 10;
      e = i % 10;
      if((i % 5 == 0) && (a == 5 || b == 5 || c == 5 || d == 5 || e == 5) ){
          f++;
      }
      i++;
    }
    cout<<f<<endl;
    return 0;
    }
    
    

    Pascal :

    var
      m,i,s:longint;
    function f(x:longint):boolean;
    var
      a:longint;
    begin
      f:=false;
      while(x<>0) do begin a:=x mod 10;x:=x div 10;if(a=5) then f:=true;end;
    end;
    begin
      read(m);
      s:=0;
      for i:=1 to m do if(f(i))and(i mod 5=0) then s:=s+1;
      write(s);
    end.
    

    Java :

    import java.util.Scanner;
    
    public class Main {
    
    	public static void main(String[] args) {
    		@SuppressWarnings("resource")
    		Scanner scanner=new Scanner(System.in);
    		int n= scanner.nextInt();
           int m=0;
    			for (int a=1;a<=n;a++) {
    				int x=a%100000/10000;
    				int b=a%10000/1000;
    				int c=a%1000/100;
    				int d=a%100/10;
    				int e=a%10;
    				if ((a%5==0)&&(b==5||c==5||d==5||e==5||x==5))				
    					m++;}
    			System.out.println(m);
    			
    	}
    
    }
    

    Python :

    n = int(input())
    count = 0
    for i in range(n):
        if i%5!=0:
            continue
        w = i//10000%10
        q = i//1000%10
        b = i//100%10
        s = i//10%10
        g = i%10
        if w==5 or q==5 or b==5 or s==5 or g==5:
            count=count+1
    print(count);
    
    
    
    • 1

    【入门】能被5整除且至少有一位数字是5的所有整数的个数

    信息

    ID
    56
    时间
    1000ms
    内存
    512MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者