1 条题解
-
0
C :
#include<stdio.h> int main() { int i; int m,n; scanf("%d%d",&m,&n); for(i=m;i<=n;i++) { if(i<1000) { if((i/100+i%10)==2*(i/10%10)) { printf("%d\n",i); } } if(i>=1000) { if((i/1000-i/100%10)==(i/100%10-i/10%10)&&(i/100%10-i/10%10)==(i/10%10-i%10)) { printf("%d\n",i); } } } return 0; }C++ :
#include <bits/stdc++.h> using namespace std; int main(){ int i,m,n,g,s,b,q; cin>>m>>n; for(i = m;i <= n;i++){ q = i / 1000; b = i / 100 % 10; s = i / 10 % 10; g = i % 10; if(i >= 1000 && q - b == b - s && b - s == s - g){ cout<<i<<endl; }else if(i >= 100 && i <= 999 && b - s == s - g){ cout<<i<<endl; } } }Java :
import java.util.Scanner; public class Main{ public static void main(String args[]){ Scanner in = new Scanner(System.in); int m = in.nextInt(); int n = in.nextInt(); for(int i=m;i<=n;i++){ int a = i/1000; int b = i/100%10; int c = i/10%10; int d = i%10; if(a==0&&b-c==c-d){ System.out.println(i); } if(a!=0&&b-c==c-d&&a-b==b-c){ System.out.println(i); } } } }Python :
m,n = map(int,input().split()); for i in range (m, n+1): a = i // 1000 b = i // 100 % 10 c = i // 10 % 10 d = i % 10 if a == 0 and b - c == c -d: print(i) elif a - b == b -c and b -c == c - d: print(i)
- 1
信息
- ID
- 446
- 时间
- 1000ms
- 内存
- 32MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者