C :

#include<stdio.h>
#include<stdlib.h>
int main(){
	    double eletric,money;
	scanf("%lf",&eletric);
 
    if(eletric<=150)	
        money=eletric*0.4463;//电量少于150KWh时的电费
    if(eletric>150&&eletric<=400)	
        money=150*0.4463+(eletric-150)*0.4663;//电量多于150KWh，少于400KWh时的电费
    if(eletric>400)		
        money=150*0.4463+250*0.4663+(eletric-400)*0.5663;//电量多于400KWh时的电费
    
    printf("%.1lf",money);//保留小数点1位
    printf("\n");//换行

	return 0;
}

C++ :

#include <bits/stdc++.h>
using namespace std;
int main(){
	int g,s,b,q,w,i,s1,s2,s3,k,f = 0;
	cin>>k;
	for(i = 10000;i <= 30000;i++){
		w = i / 10000;
		q = i / 1000 % 10;
		b = i / 100 % 10;
		s = i / 10 % 10;
		g = i % 10;
		
		s1 = w * 100 + q * 10 + b;
		s2 = q * 100 + b * 10 + s;
		s3 = b * 100 + s * 10 + g;
		
		if(s1 % k == 0 && s2 % k == 0 && s3 % k == 0){
			cout<<i<<endl;
			f = 1;
		}
	}
	
	if(f == 0){
		cout<<"No"<<endl;
	}
}

Java :

import java.util.*;
public class Main{
	public static void main(String[] args){
		Scanner sc = new Scanner(System.in);
		int n = sc.nextInt();
		if (n <= 150){
			System.out.println(String.format("%.1f",n*0.4463));
		}
		else if (n <= 400){
			System.out.println(String.format("%.1f",(n-150)*0.4663+66.945));
		}
		else if (n >= 401 ){
			System.out.println(String.format("%.1f",116.575+66.945+(n-400)*0.5663));
		}
	}
}

Python :

n = int(input())
if n <= 150:
    a = n * 0.4463
    print(round(a,1))
if n > 150 and n <= 400:
    a = 150 * 0.4463 + (n - 150) * 0.4663
    print(round(a,1))
if n > 400:
    a = 150 * 0.4463 + 250 * 0.4663 + (n - 400) * 0.5663
    print(round(a,1))