1 条题解

  • 0
    @ 2025-10-10 15:48:07

    C :

    #include<stdio.h>
    main() 
    {
    	int i,n,t=0,m=0;
    	scanf("%d",&n);
    	int a[n];
    	for(i=0; i<n; i++) 
    	{
    		scanf("%d",&a[i]);
    	}
    	for(i=0; i<n; i++) 
    	{
    		t++;
    		if(a[i]>a[i+1]||i==n-1) 
    		{
    			if(t>m) 
    			{
    				m=t;
    			}
    			t=0;
    		}
    
    	}
    	printf("%d",m);
    }
    

    C++ :

    #include <iostream>
    using namespace std;
    int a[10000010],n,i,ma = 0,c = 0;
    int main(){
    	cin>>n;
    	for(i = 0;i < n;i++){
    		cin>>a[i];
    	}
    	
    	for(i = 0;i < n;i++){
    		c++;
    		if(i == n - 1 || a[i] >= a[i + 1]){
    			if(c > ma) ma = c;
    			c = 0;
    		}
    	}
    	
    	cout<<ma<<endl;
    }
    
    
    

    Java :

    import java.util.Scanner;
    
    public class Main {
    	public static void main(String[] args) {
    		Scanner sc = new Scanner(System.in);
    		int n = sc.nextInt();
    		int[] a = new int[n];
    		for(int i =0;i<n;i++){
    			a[i] = sc.nextInt();
    		}
              getSum(a);
    	}
    	public static void getSum(int[] a){
    		int count = 1;int s = 0;
    		for(int i = 0;i<a.length-1;i++){
    			if(a[i+1]>a[i]){
    				count++;
    				if(count > s){
    					s = count;
    				}
    			}else{
    				if(count > s){
    					s = count;
    				}
    				count = 1;
    			}
    				
    		}
    		System.out.print(s);
    	}
    
    }
    
    

    Python :

    n=int(input())
    a=[]
    sr=input().split()
    for i in range(n):
        a.append(int(sr[i]))
    da=1
    js=1
    for i in range(1,n):
        if(a[i]>a[i-1]):
            js=js+1
        else:
            if(js>da):
                da=js
            js=1
    if(js>da):
        da=js
    print(da)
    
    • 1

    信息

    ID
    441
    时间
    1000ms
    内存
    128MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者