1 条题解

  • 0
    @ 2025-10-10 15:45:26

    C :

    #include<stdio.h>   
    
    int main(){ 
    	int a,b,c;
    	scanf("%d %d %d",&a,&b,&c);
    	
    	if(a < b){
    		int t = a;
    		a = b;
    		b = t;
    	}
    	
    	if(b < c){
    		int t = b;
    		b = c;
    		c = t;
    	}
    	
    	if(a < b){
    		int t = a;
    		a = b;
    		b = t;
    	}
    	
    	if(a - b == 1 && b - c == 1){
    		printf("TRUE");
    	}else{
    		printf("FALSE");
    	}
    
    	return 0;
    } 
    

    C++ :

    #include<iostream>
    using namespace std;
    int main(){
    	int a,b,c,t;
    	cin>>a>>b>>c;
    	if(a>b){
    		t=a;
    		a=b;
    		b=t;
    		
    	}
    	if(b>c){
    		t=b;
    		b=c;
    		c=t;
    	}
    	if(a>b){
    		t=a;
    		a=b;
    		b=c;
    	}
    	if(c-1==b&&b-1==a){
    		cout<<"TRUE"<<endl;
    	}else{
    		cout<<"FALSE"<<endl;
    	}
    	
    }
    
    

    Pascal :

    var a,b,c,t:longint;
    begin
      read(a,b,c);
      if a<b then begin t:=a;a:=b;b:=t; end;
      if b<c then begin t:=b;b:=c;c:=t; end;
      if a<b then begin t:=a;a:=b;b:=t; end;
      if (a-1=b)and(b-1=c)and(c+2=a) then
       writeln('TRUE') else
        writeln('FALSE');
    end.
    

    Java :

    import java.util.Scanner;
    
    public class Main {
    
    	public static void main(String[] args) {
    		@SuppressWarnings("resource")
    		Scanner scanner=new Scanner(System.in);
    		int x=scanner.nextInt();
    		int y=scanner.nextInt();
    		int z=scanner.nextInt();
    		if (((2*x==y+z)&&(x-y==1||x-z==1))||((2*y==x+z)&&(y-x==1||y-z==1))||((2*z==y+x)&&(z-y==1||z-x==1)))
    		
    		System.out.print("TRUE");	
    		else System.out.print("FALSE");	
    		}
    }
    

    Python :

    a,b,c = map(int,input().split());
    # a>b>c
    if a < b:
        t=a
        a=b
        b=t 
    if a < c:
        t=a
        a=c
        c=t 
    if b < c:
        t=b
        b=c
        c=t
    if a-b==1 and b-c==1:
        print('TRUE')
    else :
        print('FALSE')
    
    • 1

    信息

    ID
    40
    时间
    1000ms
    内存
    512MiB
    难度
    10
    标签
    递交数
    1
    已通过
    1
    上传者