1 条题解

  • 0
    @ 2025-10-10 15:46:00

    C++ :

    #include <bits/stdc++.h>
    using namespace std;
    
    int main(){
    	int n,a[110],g,s,b,q,i;
    	cin>>n;
    	for(i = 0;i < n;i++){
    		cin>>a[i]; 
    	} 
    	
    	//求完美偶数
    	for(i = 0;i < n;i++){
    		q = a[i] / 1000;
    		b = a[i] / 100 % 10;
    		s = a[i] / 10 % 10;
    		g = a[i] % 10;
    		if(a[i] >= 10 && a[i] <= 99 || a[i] >= 1000 && a[i] <= 9999){
    			if(a[i] % 2 == 0 && q % 2 == 0 && b % 2 == 0 && s % 2 == 0 && g % 2 == 0){
    				cout<<a[i]<<endl;
    			} 
    		} 
    	} 
    }
    
    

    Java :

    import java.util.Scanner;
    
    
    
    public class Main {
    
    	public static void main(String[] args) {
    		Scanner sc=new Scanner(System.in);
    		int n=sc.nextInt();
    		int[] a=new int[n];
    		for(int i=0;i<n;i++){
    			a[i]=sc.nextInt();
    		}
    		wanMei(a);
    	}
    	public static void wanMei(int[] a){
    		for(int i=0;i<a.length;i++){
    			int g=a[i]%10;
    			int s=a[i]/10%10;
    			int b=a[i]/100%10;
    			int q=a[i]/1000;
    			if((a[i]>=10&&a[i]<=99&&g%2==0&&s%2==0)||(a[i]>=1000&&a[i]<=9999&&g%2==0&&s%2==0&&b%2==0&&q%2==0)){
    				System.out.println(a[i]);
    			}
    		}
    	}
    	
    	
    }
    

    Python :

    n = int(input())
    m = input().split()
    l = []
    
    for v in m:
        l.append(int(v))
    for i in range(0, n):
        c = 0
        p = []
        t = l[i]
        # 短除法拆位,并把每一位放入p列表中
        while t > 0:
            p.append(t % 10)
            t //= 10
        # 循环遍历p列表,求出p列表中偶数的个数
        for j in p:
            if j % 2 == 0:
                c += 1
        # l[i]%2是判断整个数是否是偶数,len(p)%2是判断位数是否是偶数,c==len(p)是判断每一位上的数是否是偶数
        if l[i] % 2 == 0 and len(p) % 2 == 0 and c == len(p):
            print(l[i])
    
    
    • 1

    信息

    ID
    377
    时间
    1000ms
    内存
    256MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
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