1 条题解
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0
C :
#include<stdio.h> int main(){ int a[10],i; for(i=0;i<10;i++){ scanf("%d",&a[i]); } int h,ct=0; scanf("%d",&h); for(i=0;i<10;i++){ if(h+30>=a[i]){ ct++; } } printf("%d",ct); return 0; }C++ :
#include <bits/stdc++.h> using namespace std; int main(){ int a[10],h,c = 0; int i; for(i = 0;i < 10;i++){ cin>>a[i]; } cin>>h; for(i = 0;i < 10;i++){ if(h + 30 >= a[i]){ c++; } } cout<<c<<endl; return 0; }Pascal :
var reads,for1,Hecan:integer; apple:array[1..10] of integer; begin for for1:=1 to 10 do read(apple[for1]); readln(reads); readln; for for1:=1 to 10 do if reads+30>=apple[for1] then inc(Hecan); writeln(Hecan); readln; end.Java :
import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner sc=new Scanner(System.in); int[] a=new int[10]; for(int i=0;i<10;i++){ a[i]=sc.nextInt(); } int n=sc.nextInt(); int k=getNum(a,n); System.out.println(k); } public static int getNum(int[] a,int n){ int k=0; for(int i=0;i<a.length;i++){ if(a[i]<=n+30){ k++; } } return k; } }Python :
s = input().split() n = int(input()) l = [] c = 0 for v in s: l.append(int(v)) for i in range(0, len(l)): if n + 30 >= l[i]: c += 1 print(c)
- 1
信息
- ID
- 368
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者