1 条题解

  • 0
    @ 2025-10-10 15:46:00

    C :

    #include<stdio.h>
    int main(){
    	int a[10],i;
    	for(i=0;i<10;i++){
    		scanf("%d",&a[i]);
    	}
    	int h,ct=0;
    	scanf("%d",&h);
    	for(i=0;i<10;i++){
    		if(h+30>=a[i]){
    			ct++;
    		}
    	}
    	printf("%d",ct);
    	return 0;
    }
    
    

    C++ :

    #include <bits/stdc++.h>
    using namespace std;
    
    int main(){
    	int a[10],h,c = 0;
    	int i;
    	for(i = 0;i < 10;i++){
    		cin>>a[i];
    	} 
    	
    	cin>>h;
    	
    	for(i = 0;i < 10;i++){
    		if(h + 30 >= a[i]){
    			c++;
    		}
    	} 
    	
    	cout<<c<<endl;
    	 
        return 0;
    }
    
    

    Pascal :

    var reads,for1,Hecan:integer; 
        apple:array[1..10] of integer; 
    begin 
     for for1:=1 to 10 do read(apple[for1]); 
     readln(reads); 
     readln; 
     for for1:=1 to 10 do if reads+30>=apple[for1] then inc(Hecan); 
     writeln(Hecan); 
     readln; 
    end.
    
    

    Java :

    import java.util.Scanner;
    
    
    
    public class Main {
    
    	public static void main(String[] args) {
    		Scanner sc=new Scanner(System.in);
    		
    		int[] a=new int[10];
    		for(int i=0;i<10;i++){
    			a[i]=sc.nextInt();
    		}
    		int n=sc.nextInt();
    		int k=getNum(a,n);
    		System.out.println(k);
    	}
    	public static int getNum(int[] a,int n){
    		int k=0;
    		for(int i=0;i<a.length;i++){
    			if(a[i]<=n+30){
    				k++;
    			}
    		}
    		return k;
    	}
    	
    	
    }
    

    Python :

    s = input().split()
    n = int(input())
    l = []
    c = 0
    for v in s:
        l.append(int(v))
    for i in range(0, len(l)):
        if n + 30 >= l[i]:
            c += 1
    print(c)
    
    
    • 1

    信息

    ID
    368
    时间
    1000ms
    内存
    256MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者