1 条题解

  • 0
    @ 2025-10-10 15:45:59

    C :

    #include <stdio.h>
    
     
    
    void main(){
    
        int n;
    
        scanf("%d",&n);
    
        printf("%.1f%%",(2*n-1+4) * 100.0 / (n * n));
    
    }
    

    C++ :

    #include<bits/stdc++.h>
    using namespace std;
    int main(){
    int n;
    cin>>n;
    int zonggong =n*n;
    int fense = 2*n+3;
    double r = (double)fense / zonggong * 100;
    cout<<fixed<<setprecision(1)<<r<<"%";
    return 0;
    }
    

    Pascal :

    program ex_1;
    var
      a:longint;
    begin
      read(a);
      write((a+a+3)/(a*a)*100:4:1);
      write('%');
    end.
    

    Java :

    import java.util.Scanner;
    
    public class Main { 
    	public static void main(String[] args) {
    		Scanner sc=new Scanner(System.in);
    		double n=sc.nextDouble();
    		System.out.printf("%.1f%%",((n*2+3)/(n*n)*100));
    		sc.close();
    	}
    }
    

    Python :

    n=int(input())
    s=(2*n+3)/(n*n)*100
    print('{:.1f}%'.format(s))
    
    • 1

    信息

    ID
    325
    时间
    1000ms
    内存
    256MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者