1 条题解

  • 0
    @ 2025-10-10 15:45:59

    C++ :

    #include<bits/stdc++.h>
    using namespace std;
    int main(){
      string s1,s2,s3;
      cin>>s1>>s2>>s3;
      s1 = s1.substr(0,s1.length() - 1);
      s2 = s2.substr(0,s2.length() - 1);
      s3 = s3.substr(0,s3.length() - 1);
      cout<<fixed<<setprecision(1)<<80 * atoi(s1.c_str()) / 100.0 <<endl;
      cout<<fixed<<setprecision(1)<<80 * atoi(s2.c_str()) / 100.0 <<endl;
      cout<<fixed<<setprecision(1)<<80 * atoi(s3.c_str()) / 100.0 <<endl;
      cout<<fixed<<setprecision(1)<<80 * (100 - atoi(s1.c_str()) -atoi(s2.c_str()) -atoi(s3.c_str())  )/ 100.0 <<endl;
    } 
    
    

    Java :

    
    import java.util.Scanner;
    public class Main {
    
    	public static void main(String[] args) {
    		Scanner sc = new Scanner(System.in);
    		String s = sc.nextLine();
    		String[] strs = s.split(" ");
    		int left = 100;
    		for(int i=0;i<strs.length;i++) {
    			if(!strs[i].equals("")) {
    				String num = strs[i].split("%")[0];
    				int number = Integer.valueOf(num);
    				left = left -number;
    				System.out.printf("%.1f ",number/100.0 * 80);
    			}
    		}
    		System.out.printf("%.1f ",left/100.0 * 80);
    		sc.close();
    	}
    
    }
    
    

    Python :

    a,s=[input().split(),0]
    for i in a:
        print(round(int(i[:-1])/100*80,1),end=' ')
        s+=int(i[:-1])
    print(round((100-s)/100*80,1))
    
    
    • 1

    信息

    ID
    323
    时间
    1000ms
    内存
    256MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者