1 条题解

  • 0
    @ 2025-10-10 15:45:59

    C :

    #include <stdio.h>
    void main()
    {
    	int n,m;
    	double p;
    	scanf("%d %d",&n,&m);
    	if(m>=5)
    	{
    		p=n*0.0475*m+n;
    	}else if(m==3||m==4){
    		p=n*0.0425*m+n;
    	}else if(m==2){
    		p=n*0.0375*m+n;
    	}else if(m==1){
    		p=n*0.0325*m+n;
    	}
    	printf("%.1f",p);
    	  
    }
    

    C++ :

    #include<bits/stdc++.h>
    using namespace std;
    int main(){
        int n ,m ;
        double s;
        cin>>n>>m;
        if(m==1){
        	s=n*0.0325*m+n;
    	}else if (m==2){
    		s=n*0.0375*m+n;
    	}else if (m==3 || m==4){
    		s=n*0.0425*m+n;
    	}else{
    		s=n*0.0475*m+n;
    	}
    	cout<<fixed<<setprecision(1)<<s<<endl;
    }
    

    Pascal :

    var a,b:longint;
    c:real;
    begin
    read(a,b);
    if b=1 then c:=a*3.25/100*b
           else if b=2 then c:=a*3.75/100*b            
                       else if (b=3) or (b=4) then c:=a*4.25/100*b
                                   else c:=a*4.75/100*b;
                                   c:=c+a;
                                   write(c:0:1);
    end.
    

    Java :

    import java.util.*;
    public class Main {
    	public static void main(String[] args){
    		Scanner sc = new Scanner(System.in);
    		int n = sc.nextInt();
    		int m = sc.nextInt();
    		double s = 0;
    		if(m == 1){
    			s = n * (1 + 0.0325);
    		}
    		if(m == 2){
    			s = n * 0.0375 * m + n;
    		}
    		if(m >= 3 && m <= 4){
    			s = n * 0.0425 * m + n;	
    		}
    		if(m >= 5){
    			s = n * 0.0475 * m + n;
    		}
    		System.out.println(String.format("%.1f",s));
    	}
    }	
    

    Python :

    a,b=map(int,input().split())
    if b==1:
        S=a*(1+0.0325)
    if b==2:
        S=a*0.0375*2+a
    if 3<=b<=4:
        S=a*0.0425*b+a
    if 5<=b:
        S=a*0.0475*b+a
    print('%.1f'% S)
    
    • 1

    信息

    ID
    321
    时间
    1000ms
    内存
    256MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者