1 条题解

  • 0
    @ 2025-10-10 15:45:59

    C :

    #include<stdio.h>
    void main()
    {
    	int r1,r2;
    	double s,p=3.14;
    	scanf("%d%d",&r1,&r2);
    	s=p*r1*r1-p*r2*r2;
    	printf("%.2f",s);
    	
    }
    

    C++ :

    #include<bits/stdc++.h>
    using namespace std;
    
    int main(){
    	int r1,r2;
    	double s,pi = 3.14;
    	cin>>r1>>r2;
    	s = pi * r1 * r1 - pi * r2 * r2;
    	cout<<fixed<<setprecision(2)<<s<<endl; 
    	 
        return 0;
    }
    
    

    Pascal :

    var
            i,j,n,m:integer;
    begin
            read(n,m);
            writeln((n*n-m*m)*3.14:0:2);
    end.
    

    Java :

    import java.util.Scanner;
    
    public class Main {
    
    	public static void main(String[] args) {
    		Scanner sc = new Scanner(System.in);
    		int r1 = sc.nextInt();
    		int r2 = sc.nextInt();
    		double pi = 3.14;
    		double s1,s2,s3;
    		s1 = pi * r1 * r1;
    		s2 = pi * r2 * r2;
    		s3 = s1 - s2;
    		System.out.printf("%.2f",s3);
    	}
    }
    

    Python :

    a,b=map(int,input().split())
    s=a*a*3.14-b*b*3.14
    print('{:.2f}'.format(s))
    
    • 1

    信息

    ID
    318
    时间
    1000ms
    内存
    256MiB
    难度
    10
    标签
    递交数
    2
    已通过
    1
    上传者