1 条题解

  • 0
    @ 2025-10-10 15:45:59

    C :

    #include <stdio.h>
    void main()
    
    {
    	double i,r,s,p=3.14;
    	scanf("%lf",&i);
    	r=i/2.0/p;
    	s=3.14*r*r; 
    	printf("%.2f",s);
     }
    

    C++ :

    #include<bits/stdc++.h>
    using namespace std;
    
    int main(){
    	double s,c,r,pi = 3.14;
    	cin>>c;
    	r = c / (2 * pi);
    	s = pi * r * r;
    	cout<<fixed<<setprecision(2)<<s<<endl;
    	 
        return 0;
    }
    
    

    Pascal :

    var
      c,s:real;
    begin
      read(c);
      s:=c/6.28;
      s:=s*s*3.14;
      write(s:0:2);
    end.
    

    Java :

    import java.util.Scanner;
    
    public class Main {
    
    	public static void main(String[] args) {
    		Scanner sc = new Scanner(System.in);
    		double x = sc.nextDouble();
    		double pi = 3.14;
    		//定义面积为s
    		double s ;
    		double r = x /(2*pi);
    		s = pi * r * r;
    		System.out.printf("%.2f",s);
    	}
    }
    

    Python :

    # 接受输入周长
    x = float(input())
    # 圆周率3.14
    p = 3.14
    # 计算半径
    r = x / (2 * p)
    # 计算面积
    s = r * r * p
    print('%.2f' % s)
    
    
    • 1

    信息

    ID
    317
    时间
    1000ms
    内存
    256MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者