1 条题解

  • 0
    @ 2025-10-10 15:45:58

    C :

    #include<stdio.h>
    main()
    {
    	int a,b,c;
    	scanf("%d",&a);
    	if(a>10)
    	{   b=375/120;
    	    printf("%d",b+1);
        }
    	else if(a>7)
    	{  c=225/120;
    	   printf("%d",c+1);
        }
    	else if (a>3)
    	printf("%d",120/75);
    }
    

    C++ :

    #include <iostream>
    using namespace std;
    
    int main(){
    	int n,m,p;
    	cin>>n;
    	if(n >= 10){
    		m = 25 * 3 * 5;	
    	}else if(n >= 7){
    		m = 15 * 3 * 5;
    	}else if(n >= 3){
    		m = 5 * 3 * 5;	
    	}
    	if(m % 120 == 0){
    		p = m / 120;
    	}else{
    		p = m / 120 + 1;
    	}
    	cout<<p<<endl;
    	return 0;
    }
    

    Pascal :

    var a,b,c:longint;
    begin
    read(a);
    if a>10 then b:=25*5
             else if (a>=7) and (a<=10) then b:=15*5
                                        else if (a>=3) then b:=5*5;
                                        a:=120;
                                        b:=b*3;
                                        if b mod a=0 then c:=b div a
                                                      else c:=b div a+1;
                                                      write(c);
                                                      end.
    

    Java :

    import java.util.Scanner;
    
    public class Main {
    
    	public static void main(String[] args) {
           Scanner sc = new Scanner(System.in);
           int a=sc.nextInt();
          
        
          if(a>10) {
        	  
        	  if((25*3*5)%120==0){System.out.println((25*3*5)/120);}
        	  else {System.out.println((25*3*5)/120+1);}
          }
     
       if(a<=10&&a>7) {
        	  
        	  if((15*3*5)%120==0){System.out.println((15*3*5)/120);}
        	  else {System.out.println((15*3*5)/120+1);}
          }
       if(a<=7&&a>3) {
     	  
     	  if((5*3*5)%120==0){ System.out.println((5*3*5)/120); }
     	  else {System.out.println((5*3*5)/120+1);}
       }
    sc.close();
    	}
    
    }
    
    

    Python :

    n=int(input())
    if 3<= n <=6:
        s=5*3*5
    elif 7<= n <=10:
        s=15*3*5
    elif n > 10 :
        s=25*3*5
    
    if s % 120==0 :
        print(s//120)
    else:
            print(s//120+1) 
    
    • 1

    信息

    ID
    290
    时间
    1000ms
    内存
    256MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者