1 条题解
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0
C :
#include<stdio.h> void main() { int n; double p; scanf("%d",&n); if(n>=30){ p=n; }else if(n>=20&&n<=29){ p=1.2*n; }else if(n>=10&&n<=19){ p=1.5*n; }else{ p=1.8*n; } printf("%.1f",p); }C++ :
#include <bits/stdc++.h> using namespace std; int main(){ int a; double b; cin>>a; if(a >= 30){ b = a * 1; }else if(a >= 20){ b = a *1.2; }else if(a >= 10){ b = a * 1.5; }else{ b = a * 1.8; } cout<<fixed<<setprecision(1)<<b<<endl; return 0; }Pascal :
var a:longint; b:real; begin read(a); if a>=30 then b:=a else if a>=20 then b:=a*1.2 else if a>=10 then b:=a*1.5 else b:=a*1.8; write(b:0:1); end.Java :
import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int a = sc.nextInt(); double s = 0 ; if(a>=30) { s = (double)a; }else if (a>=20 ) { s = 1.2* (double)a ; }else if (a>=10) { s = 1.5*(double)a ; }else { s = 1.8*(double)a ; } System.out.println(s); } }Python :
n=int(input()) if n>=30: s=n elif n>=20: s=n*1.2 elif n>=10: s=n*1.5 else: s=n*1.8 print('%.1f'%s)
- 1
信息
- ID
- 284
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者