1 条题解

  • 0
    @ 2025-10-10 15:45:58

    C :

    #include<stdio.h>
    void main()
    {
    	int n;
    	double p;
    	scanf("%d",&n);
    	if(n>=30){ 
    		p=n;
     	}else if(n>=20&&n<=29){
     		p=1.2*n;
    	}else if(n>=10&&n<=19){
    		p=1.5*n;
    	}else{
    		p=1.8*n;
    	}
    	printf("%.1f",p);
    } 
    

    C++ :

    #include <bits/stdc++.h>
    using namespace std;
    int main(){
       int a;
       double b;
       cin>>a;
       if(a >= 30){
       	  b = a * 1;
       }else if(a >= 20){
       	  b = a *1.2;
       }else if(a >= 10){
       	  b = a * 1.5;
       }else{
       	  b = a * 1.8;
       } 
       cout<<fixed<<setprecision(1)<<b<<endl;
       return 0;
    }
    
    

    Pascal :

    var a:longint;
    b:real;
    begin
    read(a);
    if a>=30 then b:=a
    else if a>=20 then b:=a*1.2
    else if a>=10 then b:=a*1.5
    else b:=a*1.8;
    write(b:0:1);
    end.
    

    Java :

    import java.util.Scanner;
    
    public class Main {
    	public static void main(String[] args) {
    		Scanner sc = new Scanner(System.in);
    		int a = sc.nextInt();
    		double s = 0 ;
    		if(a>=30) {
    			s = (double)a;
    		}else if (a>=20 ) {
    			s = 1.2* (double)a ;
    		}else if (a>=10) {
    			s = 1.5*(double)a ;
    		}else {
    			s = 1.8*(double)a ;	
    		}
    		System.out.println(s);
    	}
    }
    
    

    Python :

    n=int(input())
    if n>=30:
        s=n
    elif n>=20:
        s=n*1.2
    elif n>=10:
        s=n*1.5
    else:
        s=n*1.8
    print('%.1f'%s)
    
    
    • 1

    信息

    ID
    284
    时间
    1000ms
    内存
    256MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者