1 条题解

  • 0
    @ 2025-10-10 15:45:58

    C :

    #include <stdio.h>
    void main()
    {
    	int n;
    	scanf("%d",&n);
    	if(n%2==0){
    		printf("%d\n",2);
    	}
    	if(n%3==0){
    		printf("%d\n",3);
    	}
    	if(n%5==0){
    		printf("%d\n",5);
    	}
    	if(n%7==0){
    		printf("%d\n",7);
    	}
    	  
    }
    

    C++ :

    #include <iostream>
    using namespace std;
     
    int main(){
    	int n;
    	cin>>n;
    	if(n % 2 == 0){
    		cout<<2<<endl;
    	}
    	
    	if(n % 3 == 0){
    		cout<<3<<endl;
    	}
    	
    	if(n % 5 == 0){
    		cout<<5<<endl;
    	}
    	
    	if(n % 7 == 0){
    		cout<<7<<endl;
    	}
    }
    
    

    Pascal :

    var a:longint;
    begin
    read(a);
    if a mod 2=0 then writeln('2');
    if a mod 3=0 then writeln('3');
    if a mod 5=0 then writeln('5');
    if a mod 7=0 then writeln('7');
    end.
    

    Java :

    import java.util.Scanner;
    public class Main {
    		public static void main(String[] args) {
    			Scanner sc = new Scanner(System.in);
    			int n = sc.nextInt();
    			if(n % 2 == 0){
    				System.out.println(2);
    			}if(n % 3 == 0){
    				System.out.println(3);
    			}if(n % 5 == 0){
    				System.out.println(5);
    			}if(n % 7 == 0){
    				System.out.println(7);
    			}
    		}
    }
    

    Python :

    n = int(input())  
    if n % 2 == 0:
        print(2)
    if n % 3 == 0:
        print(3)
    if n % 5 == 0:
        print(5)
    if n % 7 == 0:
        print(7)
    
    
    • 1

    【入门】请问一个整数n能够被2、3、5、7中哪些数整除

    信息

    ID
    279
    时间
    1000ms
    内存
    256MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者