1 条题解

  • 0
    @ 2025-10-10 15:45:57

    C :

    #include<stdio.h>
    #include<math.h>
    
    int main()
    {
     int x,y,z;
     for(x = 1;x < 9;x ++) {
      for(y = 1;y < 12;y ++)  {
       z = 36-x-y;
       if(z%2==0) {
        if(4*x + y*3 + z/2 == 36)
         printf("%d %d %d\n",x,y,z);
       } 
      }
     } 
     return 0;
    
    }
    
    
    
    

    C++ :

    #include <iostream> 
    using namespace std; 
    int main(){ 
        int i,j,x,y;
        //男人的数量
    	for(i = 1;i <= (36 - 3 - 1) / 4;i++){
    		//剩余的砖数量 
    		x = 36 - i * 4;
    		//女人的数量
    		for(j = 1;j <= (x - 1) / 3;j++){
    			//剩余的砖数量
    			y = x - j * 3;
    			if(i + j + y * 2 == 36){
    				cout<<i<<" "<<j<<" "<<y * 2<<endl; 	
    			}
    			
    		} 
    	} 
    } 
    

    Pascal :

    var i,j,k:longint;
    begin
    for i:=1 to 36 do
    for j:=1 to 36 do
    for k:=1 to 72 do
    if ((i*4)+(j*3)+(k div 2)=36)and(i+j+k=36)and(k mod 2=0) then writeln(i,' ',j,' ',k);
    end.
    

    Java :

    import java.util.Scanner;
    public class Main {
    	public static void main(String[] args){
    		//Scanner sc = new Scanner(System.in);
    		int x,y,z;
    		for(x=1;x<9;x++){
    			for(y=1;y<12;y++){
    				z=36-x-y;
    				if(4*x+3*y+z/2==36&&z%2==0){
    					System.out.println(x+" "+y+" "+z);
    				}
    			}
    		}
    	}
    }
    
    
    

    Python :

    for i in range(1, 10):
        for j in range(1, 13):
            for k in range(1, 73):
                if 4 * i + 3 * j + 1 * k == 36 and i + j + 2 * k == 36:
                    print(i, end=' ')
                    print(j, end=' ')
                    print(2 * k)
    print()
    
    
    • 1

    信息

    ID
    244
    时间
    1000ms
    内存
    256MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
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