C :

#include<stdio.h>
int main(){
	int n,x,y,i,j;
	scanf("%d%d%d",&n,&x,&y);
	for(i=2;x*i<n;i=i+2){
		for(j=2;y*j<n;j=j+2){
			if(i*x+j*y==n){
			printf("%d %d\n",i,j);
			}
		}
		

	}
	return 0;
}

C++ :

#include <iostream>
using namespace std;
int main(){
    int n,x,y,i,t;
    cin>>n>>x>>y;
    
    //循环大碗可能买到的数量 
    for(i = 1;i <= (n - y) / x;i++){
    	//计算买了大碗剩余的钱 
    	t = n - i * x;
    	
    	//如果剩余的钱正好够买小碗，且大碗小碗的只数都是偶数
		if(t % y == 0 && i % 2 == 0 && t / y % 2 == 0){
			cout<<i<<" "<<t / y<<endl;
		}
	}  
}

Java :

import java.util.Scanner;
public class Main {
	public static void main(String[] args){
		Scanner sc = new Scanner(System.in);
		int n=sc.nextInt();
		int x=sc.nextInt();
		int y=sc.nextInt();
		for(int a=2;a<=n/x;a++){
			for(int b=2;b<=n/y;b++){
				if(a*x+b*y==n&&a%2==0&&b%2==0){
					System.out.println(a+" "+b);
				}
			}
		}
	}
}

Python :

s = input().split()
n = int(s[0])
x = int(s[1])
y = int(s[2])
for i in range(1, n // x):
    for j in range(1, n // y):
        if i % 2 == 0 and j % 2 == 0 and x * i + y * j == n:
            print(i, end=' ')
            print(j)