1 条题解

  • 0
    @ 2025-10-10 15:45:57

    C :

    #include <stdio.h>
    void main(){
    	int n,x,y;
    	scanf("%d %d %d",&n,&x,&y);
    	int i,j;
    	int a = 0;
    	for (i=1;i<=n/x;i++){
    		for(j=1;j<=n/y;j++){
    			if(i*x+j*y==n){
    				if(i>=a)
    					a=i;
    			}
    		}
    	}
    	printf("%d %d",a,(n-a*x)/y);
    } 
    

    C++ :

    #include <iostream>
    
    using namespace std;
    
    int main(){
    	int x,y,n,i,m=0;
    	cin>>n>>x>>y;
    	for(i=1;i*x<n;i++){
    		if((n-i*x)%y==0&&(n-i*x)/y!=0)m=i;
    	}
    	cout<<m<<" "<<(n-m*x)/y<<endl;
    }
    

    Pascal :

    var x,a,b,n,i,c:integer;
    begin
      readln(x,a,b);
      n:=x div a;
      for i:=n downto 1 do
      begin
        if((x-a*i) mod b=0) and ((x-a*i) div b>=1) then
        begin
           writeln(i,' ',(x-a*i) div b);
           break;
        end;
      end;
    end.
    

    Java :

    import java.util.*;
    public class Main{
    	public static void main(String[] args) {
    		Scanner in = new Scanner(System.in);
    		int n=in.nextInt();
    		int x=in.nextInt();
    		int y=in.nextInt();
    		w:for(int i=n/x;i>0;i--){
    			for(int j=1;j<=(n-i*x)/y;j++){
    				if(i*x+y*j==n&&i!=0&&j!=0){
    					System.out.println(i+" "+j);
    					break w;
    				}
    			}
    		}
    	}
    
    }
    

    Python :

    n, x, y = map(int, input().split())
    j = []
    m = []
    for i in range(1, n // x + 1):
        if(n - i * x) > 0 and (n - i * x) % y == 0:
            l = (n - i * x) // y
            j.append(i)
            m.append(l)
            pass
    print(max(j), min(m))
    
    • 1

    信息

    ID
    215
    时间
    1000ms
    内存
    256MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者