1 条题解

  • 0
    @ 2025-10-10 15:45:26

    C :

    #include<stdio.h>
    int main()
    {
    	int a;
    	scanf("%d",&a);
    	int b=a/100%10;
    	int c=a/10%10;
    	int d=a/1%10;
    	printf("%d\n",d*100+c*10+b+a);
    		
    	return 0;
    }
    

    C++ :

    #include <iostream>
    #include <iomanip>
    using namespace std;
    
    int main(){
        int n;
        cin>>n;
        cout<<n+n/100+n/10%10*10+n%10*100<<endl;
    }
    

    Pascal :

    var a,k,g,s,b:longint;
    begin
      read(a);
      g:=a mod 10;
      s:=a div 10 mod 10;
      b:=a div 100;
      k:=g*100+s*10+b;
      writeln(k+a);
    end.
    
    

    Java :

    import java.util.Scanner;
    public class Main {
    	public static void main(String[] args) {
    		Scanner scanner=new Scanner(System.in);
    		String numberString=scanner.nextLine();
    		char[] charArray=numberString.toCharArray();
    		String numberString_new="";
    		for(int i=charArray.length-1;i>=0;i--){
    			numberString_new=numberString_new+String.valueOf(charArray[i]);
    		}		System.out.println(Integer.valueOf(numberString.trim())+Integer.valueOf(numberString_new.trim()));
    	}
    }
    

    Python :

    r = int(input())
    a = r // 100;
    b = r // 10 % 10
    c = r % 10;
    print(c * 100 + b * 10 + a + r)
    
    • 1

    信息

    ID
    19
    时间
    1000ms
    内存
    512MiB
    难度
    10
    标签
    递交数
    2
    已通过
    2
    上传者