1 条题解

  • 0
    @ 2025-10-10 15:45:28

    C :

    #include<stdio.h>
    
    int main()
    {
    	int n;
    	scanf("%d",&n);
    	char a[n],i;
    	for(i=0;i<n;i++){
    		scanf("%s",&a[i]);
    	}
    	int s=0;
    		for(i=0;i<n;i++){
    			if(a[0]>='A'&&a[0]<='G'||a[0]>='R'&&a[0]<='T'){
    				s++;
    		}
    		break;
    				}
    				printf("%d",n-s);
    	
    	
    
    
    
    return 0;
    }
    
    

    C++ :

    #include<bits/stdc++.h>
    using namespace std;
    int main(){
    	int n,i,c=0;
    	string s;
    	cin>>n;
    	for (i=1;i<=n;i++) {
    		cin>>s;
    		if (s[0]>='H' && s[0]<='Q') {
    			c++;	
    		} 
    		if (s[0]>='U' && s[0]<='Z') {
    			c++;
    		}
    	}
    	cout<<c<<endl;
    
    	return 0;
    }
    
    

    Java :

    import java.util.Scanner;
    public class Main{
    	public static void main(String[] args) {
    		Scanner scanner=new Scanner(System.in);
    		String n=scanner.nextLine();
    		int num_jq=0;
    		for(int i=0;i<Integer.valueOf(n);i++){
    			String hm=scanner.nextLine();
    			if(!(hm.startsWith("A")||hm.startsWith("B")||hm.startsWith("C")||hm.startsWith("D")||hm.startsWith("E")||
    					hm.startsWith("F")||hm.startsWith("G")||hm.startsWith("R")||hm.startsWith("S")||hm.startsWith("T"))){
    				num_jq++;
    			}
    		}
    		System.out.println(num_jq);
    	}
    }
    

    Python :

    n=int(input())
    js=0
    for i in range(1,n+1):
        sr=input()
        if (sr[0]>="A" and sr[0]<="G") or (sr[0]>="R" and sr[0]<="T"):
            js=js+1
    print(n-js)
    
    • 1

    信息

    ID
    176
    时间
    1000ms
    内存
    32MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者