1 条题解
-
0
C :
#include<stdio.h> main() { int i,n,b=0,c=0; scanf("%d",&n); int a[n]; for(i=0;i<n;i++) { scanf("%d",&a[i]); } for(i=0;i<n;i++) { if(a[i]%2!=0) { b+=a[i]; } else c+=a[i]; } printf("%d\n%d",b,c); }C++ :
#include <iostream> using namespace std; int main(){ int i,n,j=0,o=0; int a[5000]; cin>>n; for(i=0;i<n;i++){ cin>>a[i]; if(a[i]%2!=0){ j=j+a[i]; }else{ o=o+a[i]; } } cout<<j<<endl; cout<<o<<endl; }Pascal :
var a:array[1..100000] of longint; n,i,x,y:longint; begin read(n); for i:=1 to n do read(a[i]); for i:=1 to n do begin if a[i] mod 2=1 then x:=x+a[i] else y:=y+a[i]; end; write(x,' ',y); end.Java :
import java.util.Scanner; public class Main { public static void main(String[] args) { @SuppressWarnings("resource") Scanner sc=new Scanner(System.in); int a=sc.nextInt(); int[] n=new int[a]; for(int i=0;i<a;i++) { n[i]=sc.nextInt(); } int j=0,o=0; for(int i=0;i<n.length;i++) { if(n[i]%2==0) { o+=n[i]; } else { j+=n[i]; } }System.out.println(j); System.out.println(o); } }Python :
n=int(input()) l1=[] for i in range(1,n+1): a=int(input()) l1.append(a) a=0 b=0 for i in range(0,n): if l1[i]%2==0: a+=l1[i] else: b+=l1[i] print(b,a)
- 1
信息
- ID
- 169
- 时间
- 1000ms
- 内存
- 512MiB
- 难度
- 10
- 标签
- 递交数
- 10
- 已通过
- 3
- 上传者