1 条题解

  • 0
    @ 2025-10-10 15:45:28

    C :

    #include<stdio.h>
    main()
    {
    	int i,n,b=0,c=0;
    	scanf("%d",&n);
    	int a[n];
    	for(i=0;i<n;i++)
    	{
    		scanf("%d",&a[i]);
    	}
    	for(i=0;i<n;i++)
    	{
    		if(a[i]%2!=0)
    		{
    			b+=a[i];
    		}
    		else
    		c+=a[i];
    	}
    	printf("%d\n%d",b,c);
    }
    

    C++ :

    #include <iostream>
    using namespace std;
    
    int main(){
    	int i,n,j=0,o=0;
    	int a[5000];
    	cin>>n;
    	for(i=0;i<n;i++){
    		cin>>a[i];
    		if(a[i]%2!=0){
    			j=j+a[i];
    		}else{
    			o=o+a[i];
    		}
    	}
    	cout<<j<<endl;
    	cout<<o<<endl;
    	
    }
    

    Pascal :

    var a:array[1..100000] of longint;
        n,i,x,y:longint;
    begin
    read(n);
    for i:=1 to n do
    read(a[i]);
    for i:=1 to n do
    begin
    if a[i] mod 2=1 then x:=x+a[i]
    else y:=y+a[i];
    end;
    write(x,' ',y);
    end.
    

    Java :

    import java.util.Scanner;
    public class Main {
    	public static void main(String[] args) {
    		@SuppressWarnings("resource")
    		Scanner sc=new Scanner(System.in);
    		int a=sc.nextInt();
    		int[] n=new int[a];
    		for(int i=0;i<a;i++) {
    			n[i]=sc.nextInt();		
    		}	
    		int j=0,o=0;
    		for(int i=0;i<n.length;i++) {
    			if(n[i]%2==0) {
    				o+=n[i];
    				
    		}	
    			else {
    				j+=n[i];				
    			}
    		}System.out.println(j);
    		System.out.println(o);
      }
    }
    

    Python :

    n=int(input())
    l1=[]
    for i in range(1,n+1):
        a=int(input())
        l1.append(a)
    a=0
    b=0
    for i in range(0,n):
        if l1[i]%2==0:
            a+=l1[i]
        else:
            b+=l1[i]
    print(b,a)
    
    • 1

    信息

    ID
    169
    时间
    1000ms
    内存
    512MiB
    难度
    10
    标签
    递交数
    10
    已通过
    3
    上传者