1 条题解

  • 0
    @ 2025-10-10 15:45:27

    C :

    #include<stdio.h>
    char a[200];
    int pan(int a,int b);
    int main()
    {
    	scanf("%s",a);
    	int x=0;
    	for(;a[x]!='\0';x++);
    	int ans=x;
    	while(pan(0,x-1))
    	{
    		ans/=2;
    		x/=2;
    	}
    	printf("%d",ans);
    	return 0;
    }
    int pan(int m,int n)
    {
        int mid=(m+n)/2;
        for(int i=m;i<=mid;i++)
        if(a[i]!=a[n-i]) return 0;
        return 1;
    }
    

    C++ :

    #include <iostream>
    #include <cstring>
    using namespace std;
    
    //判断是否回文
    bool huiwen(char s[]){
    	bool f = true;
    	int i;
    	for (i = 0;i < strlen(s) / 2;i++){
    		if (s[i] != s[strlen(s) - i - 1]){
    			f = false;
    			break;
    		}
    	}
    	return f;
    } 
    
    int main(){
    	char s[2000];
    	gets(s);
    	int i;
    	while (huiwen(s) && strlen(s) % 2 == 0){
    		s[strlen(s) / 2] = '\0';
    	}
        cout<<strlen(s)<<endl;
    }
    

    Pascal :

    var str:string;
        b,i,x,c:longint;
    begin
    read(str);
    b:=length(str);
    while b mod 2=0 do
    begin
    c:=b;
    for i:=1 to b do
    if str[i]<>str[c-i+1] then  begin x:=1;break;end;
    if x=1 then break
           else b:=b div 2;
    end;
    write(b);
    end.
    

    Java :

    import java.util.Scanner;
    
    public class Main {
    	public static void main(String[] args) {
    		Scanner sc = new Scanner(System.in);
    		String str = sc.nextLine();
    		while(str.substring(0, str.length()/2).equals(str.substring(str.length()/2,str.length())) ){
    			str = str.substring(0, str.length()/2);
    		}
    		String str1 = str.substring(0, str.length()/2);
    		System.out.println(str1.length());
    	}
    }
    

    Python :

    def huiwen(b):
        if b==b[::-1]:
            return 1
        else:
            return 0
    str1=input()
    while(huiwen(str1)):
        b=len(str1)
        str1=str1[0:int(b//2)]
    print(len(str1))
    
    
    
    • 1

    信息

    ID
    129
    时间
    1000ms
    内存
    512MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者