1 条题解

  • 0
    @ 2025-10-10 20:11:59

    C :

    #include<stdio.h>
    #include<stdlib.h>
    #include<string.h>
    char t[1000];
    int n;
    int tree(int k) {
    	if ((t[2*k]=='#'&&t[2*k+1]=='#')||(2*k>n&&(2*k+1>n))) return 1;
    		else 	if (2*k<=n&&t[2*k]!='#'&&(2*k+1<=n)&&t[2*k+1]!='#') return tree(2*k)&&tree(2*k+1);
    			else return 0;
    }
    
    int main(){
    	int i;
    	scanf("%s",t);
    	n=strlen(t);
    	for (i=n;i>0;i--) t[i]=t[i-1];
    	if (tree(1)) printf("Yes\n");
    		else printf("No\n");
    	
    	return 0;
    }
    
    

    C++ :

    
    #include<iostream>
    #include<cstdio>
    #include<cstring>
    #include<cmath>
    #include<algorithm>
    #include<string>
    #include<cstdlib>
    #include<queue>
    #include<vector>
    #define INF 0x3f3f3f3f
    #define PI acos(-1.0)
    #define N 1001
    #define MOD 123
    #define E 1e-6
    using namespace std;
    char s[N];
    int main()
    {
        cin>>s;
        int len=strlen(s);
        s[len]='#';
     
        int flag=true;
        for(int i=1;i<len;i+=2){
            if( (s[i]=='#'&&s[i+1]!='#') || (s[i+1]=='#'&&s[i]!='#') )
            {
                flag=false;
                break;
            }
        }
        if(flag)
            cout<<"Yes"<<endl;
        else
            cout<<"No"<<endl;
        return 0;
    }
     
    
    
    • 1

    信息

    ID
    1087
    时间
    1000ms
    内存
    512MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者