1 条题解

  • 0
    @ 2025-10-10 20:11:59

    C :

    #include<stdio.h>
    #include<string.h>
    struct tree
    {
    int data;
    int lch,rch;
    }a[100100];;
    int n;
    void bst();
    int z_order(int);
    int h_order(int);
    int main()
    {
    bst();
    z_order(1);
    printf("\n");
    h_order(1);	
    return 0;
    }
    void bst()
    {
    scanf("%d",&n);
    memset(a,0,sizeof(a));
    int x;
    for(int i=1;i<=n;i++)
    {
    scanf("%d",&x);
    a[i].data=x;
    if(i==1) continue;
    int p=1;
    while(1)
    {
    if(x<a[p].data)
    {
    if(a[p].lch!=0)
    {
    p=a[p].lch;
    continue;
    }
    else
    {
    a[p].lch=i;
    break;
    }
    }
    else
    {
    if(a[p].rch!=0)
    {
    p=a[p].rch;
    continue;
    }
    else
    {
    a[p].rch=i;
    break;
    }
    }
    }
    }
    }
    int z_order(int x)
    {
    if(x==0)return 0;
    z_order(a[x].lch);
    printf("%d ",a[x]);
    z_order(a[x].rch);
    return 0;
    }
    int h_order(int x)
    {
    if(x==0)return 0;
    h_order(a[x].lch);	
    h_order(a[x].rch);
    printf("%d ",a[x]);
    return 0;
    }
    

    C++ :

    #include<iostream>
    #include<cstdio>
    #include<cstring>
    using namespace std;
    struct tree
    {
    	int data;
    	int lch,rch;
    };
    int n;
    tree a[100100];
    void bst();
    int z_order(int);
    int h_order(int);
    int main()
    {
    	//freopen("bst5.in","r",stdin);
    	//freopen("bst5.out","w",stdout);
    	bst();
    	z_order(1);
    	cout<<endl;
    	h_order(1);	
    	return 0;
    }
    void bst()
    {
    	cin>>n;
    	memset(a,0,sizeof(a));
    	int x;
    	for(int i=1;i<=n;i++)
    	{
    		cin>>x;
    		a[i].data=x;
    		if(i==1) continue;
    		int p=1;
    		while(1)
    		{
    			if(x<a[p].data)
    			{
    				if(a[p].lch!=0)
    				{
    					p=a[p].lch;
    					continue;
    				}
    				else
    				{
    					a[p].lch=i;
    					break;
    				}
    			}
    			else
    			{
    				if(a[p].rch!=0)
    				{
    					p=a[p].rch;
    					continue;
    				}
    				else
    				{
    					a[p].rch=i;
    					break;
    				}
    			}
    		}
    	}
    }
    int z_order(int x)
    {
    	if(x==0)return 0;
    	z_order(a[x].lch);
    	cout<<a[x].data<<' ';
    	z_order(a[x].rch);
    	return 0;
    }
    int h_order(int x)
    {
    	if(x==0)return 0;
    	h_order(a[x].lch);	
    	h_order(a[x].rch);
    	cout<<a[x].data<<' ';
    	return 0;
    }
    

    Pascal :

    program bst;
    type node=^rec;
            rec=record
    		        data:longint;
    				left,right:node;
    				end;
    var  bt,p,q:node;
           n,i,j,key:longint;
    procedure qianxu(p:node);
    begin
      if p<>nil then
      begin
        write(p^.data,' ');
        qianxu(p^.left);
        qianxu(p^.right);
      end;
    end;
    procedure zhongxu(p:node);
    begin
      if p<>nil then
      begin
      zhongxu(p^.left);
      write(p^.data,' ');
      zhongxu(p^.right);
      end;
    end;
    procedure houxu(p:node);
    begin
      if p<>nil then
      begin
      houxu(p^.left);
      houxu(p^.right);
      write(p^.data,' ');
      end;
    end;
    Procedure insert(var pnode:node; key:longint);
    var tempnode:node;
    begin
      new(tempnode);
      tempnode^.data:=key;
      tempnode^.left:=nil; tempnode^.right:=nil;
      if pnode=nil then
      begin pnode:=tempnode;end
      else
       begin
        p:=pnode;q:=nil;
        While(p<>nil) do
        begin
         q:=p;
          if key<p^.data then p:=p^.left else p:=p^.right;
         end;
       if key<q^.data then q^.left:=tempnode else q^.right:= tempnode;
       end;
    End;
    begin
      begin
        readln(n);
        bt:=nil;
        for i:=1 to n do
          begin
    	  read(key);
    	  insert(bt,key);
          end;
       zhongxu(bt);writeln;
       houxu(bt);writeln;
      end;
      end.
    
    
    • 1

    信息

    ID
    1080
    时间
    1000ms
    内存
    512MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
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