1 条题解

  • 0
    @ 2025-10-10 15:45:27

    C :

    #include<stdio.h>
    #include<stdlib.h>
    #include<string.h>
    #include<ctype.h>
    int a[10001];
    int main(){
        int n,i,k=0;
        scanf("%d",&n);
        if(n==0){
        	printf("%d",0);
        	return 0;
    	}
        while(n!=0){
        	k++;
        	a[k] = n%2;
        	n = n/2;
    	}
    	for(i=k;i>=1;i--){
    		printf("%d",a[i]);
    	}
        return 0;
    }
    
    

    C++ :

    #include <iostream>
    #include <cstring>
    using namespace std;
    
    int main(){
    	int n,i = 0;
    	char s[1000] = "";
    	cin>>n;
    	while(n != 0){
    		s[i] = n % 2 + 48;
    		i++;
    		n = n / 2;
    	}
    	for (i = strlen(s) - 1;i >= 0;i--){
    		cout<<s[i];
    	}
    }
    

    Java :

    import java.util.Scanner;
    public class Main{
    	public static void main(String[] args) {
    		Scanner scanner=new Scanner(System.in);
    		Integer num=scanner.nextInt();
    	    System.out.println(Integer.toBinaryString(num));
    	}
    }
    

    Python :

    n = int( input() )
    s=''
    while n==0:
        print('0')
        break
    while n!=0:
        s = str(n % 2) + s
        n = n // 2
    print(s)
    
    • 1

    【入门】正整数N转换成一个二进制数

    信息

    ID
    103
    时间
    1000ms
    内存
    512MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者