1 条题解
-
0
C :
#include<stdio.h> #include<stdlib.h> #include<string.h> #include<ctype.h> int a[10001]; int main(){ int n,i,k=0; scanf("%d",&n); if(n==0){ printf("%d",0); return 0; } while(n!=0){ k++; a[k] = n%2; n = n/2; } for(i=k;i>=1;i--){ printf("%d",a[i]); } return 0; }C++ :
#include <iostream> #include <cstring> using namespace std; int main(){ int n,i = 0; char s[1000] = ""; cin>>n; while(n != 0){ s[i] = n % 2 + 48; i++; n = n / 2; } for (i = strlen(s) - 1;i >= 0;i--){ cout<<s[i]; } }Java :
import java.util.Scanner; public class Main{ public static void main(String[] args) { Scanner scanner=new Scanner(System.in); Integer num=scanner.nextInt(); System.out.println(Integer.toBinaryString(num)); } }Python :
n = int( input() ) s='' while n==0: print('0') break while n!=0: s = str(n % 2) + s n = n // 2 print(s)
- 1
信息
- ID
- 103
- 时间
- 1000ms
- 内存
- 512MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者